IB Chemistry: Grade 12: Practical 1: Stoichiometry Quantitative Preparation of a Salt and Yield Calculation

Quantitative preparation of a salt and yield count Introduction:          atomic number 29 (II) sulfate batch be ready by reacting copper (II) oxide with subjugate sulfuric acid. The resulting copper (II) sulfate source can wherefore be crystallized, so that a quantitative analysis may be made of the reaping formed. This can then be compared with the divinatory add up, and % yield calculated. Copper (II) sulphate crystals are CuSO4.5H2O. Therefore, the reception is:                  CuO + H2SO4 + 4H2O ® CuSO4.5H2O                  0.2 mol. 0.2 mol. 0.2 mol. Hypothesis:         According to theory, the descend of copper sulphate produced should be 159.61g. However, I believe the amount produced will be far from this. This is because the theoretical amount can never be produced exactly, even low laboratory conditions. appliance: speed of lightml meas uring cylinder (± 0.05 cm) carbonml 2M trim shoot sulphuric acid 250ml beaker (x2) (± 0.05 cm) Bunsen burner Copper (II) oxide funnel shape Filter papers Scale (± 0.0005 g) Clamp stand rule: A measuring cylinder was taken, and used to measure 100ml of 2M subjugate sulphuric acid. The acid was transferred to a 250ml beaker, and warmed with the Bunsen burner shape up not allowed to boil. Copper (II) oxide was added until in excess. The closure was filtered while let off hot, and the symmetricalness was washed off. The resulting copper (II) sulphate solution was poached until it had been cut back by approximately 50%. The solution was then allowed to crystallize.

Once crystallized, the solution was filtered to separate the crystals. The crystals were dried amongst fresh filter paper. The crystals were weighed on the scale. Results:         Amount of copper (II) oxide from taste         Theoretical weight/g                           49.94          unfeigned weight/g (± 0.0005 g)                  38.38 Yield: (38.38 / 49.94) x 100 = 76.85% % uncertainty = 0.0005 x 100 = 1.303 x 10^-5%                   38.38... If you want to get a equal to(predicate) essay, order it on our website: BestEssayCheap.com

If you want to get a full essay, visit our page: cheap essay