Assignment Week 2 Bus308

Assignment week 2 Milena I Barry Statistics for Managers Instructor Nicholas Bergan omnibus 308 June 18, 2012 4.4 call up a couple will pulsate three children. permit B concern a boy and G denote a young lady: a take back a shoetree diagram depicting the sample lay outcome for this experiment b List the sample shoes outcome that correspond to for each one of the following events: 1 All three children will have the same sexual activity {BBB,GGG} 2 Exactly two of the children will be girls {BGG,GGB,GBG} 3 Exactly one of the three children will be a girl {BBG,BGB,GBB} 4 None of the children would be a girl {BBB} c Assuming that all sample space outcomes nuclear number 18 every bit likely, find the luck of each of the events given in dissolve b 1= 2/8=1/4 2=3/8 3=3/8 4=1/8 4.20 crapper and Jane are married. The luck that John captivatees a certain television verbalise is .4. The fortune that Jane watches the rise is .5. The fortune that John watches the show, given that Jane does is .7. a come up the probability that both John and Jane watches the show P(John | Jane) * P(Jane)=P(John and Jane)/P(Jane) =(0.7)×(0.5)=0.35 b Find the probability that Jane watches the show, given that John does. P(Jane | John)=P(Jane and John)/P(John)=(0.35)/(0.4)=0.875 c Do John and Jane watch the show one by one of each other?

rationalize jour answer. P(Jane) * P(John) = (0.5) * (0.4) = 0.20 P(Jane and John) ? P(Jane) * P(John) = 0.35 ? 0.20 This means that they dont watch the show independently of each other. 5.12 Suppose the probability distributi on of a haphazard variable x can be expoun! d by the formula p(x) = X/15. for each of the values x - 1, 2,3,4 and 5. face P(x+2) = p(2) =p(2) =2/15. a. Write out the probability distribution of x x| P(x)=x/15| X*p(x)| (x^2) * P(x)| 1| 0.0667| 0.0667| 0.0667| 2| 0.1333| 0.2667| 0.5333| 3| 0.2000| 0.6000| 1.8000| 4| 0.2667| 1.0667| 4.2667| 5| 0.3333| 1.6667| 8.3333| b. Show that the probability distribution of x...If you regard to get a full essay, lay out it on our website: BestEssayCheap.com

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